Langyou Chemical
SUPPLEMENTS
Aluminum Sulfate Calcium Hydroxide Balanced Equation
On the chemical reaction of the balance between aluminum sulfate and calcium hydroxide, the balance is essential. Now the reaction between aluminum sulfate ($Al_ {2} (SO_ {4}) _ {3} $) and calcium hydroxide ($Ca (OH) _ {2} $), the two meet, and a chemical change will occur.
Aluminum ion ($Al ^ {3 +} $) in aluminum sulfate has three positive charges, sulfate ion ($SO_ {4} ^ {2 -} $) has two negative charges; calcium ion ($Ca ^ {2 +} $) in calcium hydroxide has two positive charges, and hydroxide ion ($OH ^ {-} $) has one negative charge. In the reaction, aluminum ion binds to hydroxide ion, and sulfate ion binds to calcium ion.
First look at the aluminum element, there are 2 dollars $aluminum atoms in aluminum sulfate. To make the number of aluminum atoms equal after the reaction, the coefficient before aluminum hydroxide ($Al (OH) _ {3} $) should be 2 dollars $. Looking at sulfate, there are 3 dollars $sulfate in aluminum sulfate, so the coefficient before calcium sulfate ($CaSO_ {4} $) should be 3 dollars $. At this time, in order to make the number of calcium atoms equal, the coefficient before calcium hydroxide should be 3 dollars $. And because there are 3 dollars $hydroxides in aluminum hydroxide, and 2 dollars $aluminum hydroxide contains 6 dollars $hydroxides, which is exactly the same as the number of hydroxides in 3 dollars $calcium hydroxide.
In summary, the chemical equation for the reaction of aluminum sulfate and calcium hydroxide is: $Al_ {2} (SO_ {4}) _ {3} + 3Ca (OH) _ {2} = 2Al (OH) _ {3}\ downarrow + 3CaSO_ {4} $. This formula is equal to the type and number of atoms, which is chemically reasonable.
Aluminum ion ($Al ^ {3 +} $) in aluminum sulfate has three positive charges, sulfate ion ($SO_ {4} ^ {2 -} $) has two negative charges; calcium ion ($Ca ^ {2 +} $) in calcium hydroxide has two positive charges, and hydroxide ion ($OH ^ {-} $) has one negative charge. In the reaction, aluminum ion binds to hydroxide ion, and sulfate ion binds to calcium ion.
First look at the aluminum element, there are 2 dollars $aluminum atoms in aluminum sulfate. To make the number of aluminum atoms equal after the reaction, the coefficient before aluminum hydroxide ($Al (OH) _ {3} $) should be 2 dollars $. Looking at sulfate, there are 3 dollars $sulfate in aluminum sulfate, so the coefficient before calcium sulfate ($CaSO_ {4} $) should be 3 dollars $. At this time, in order to make the number of calcium atoms equal, the coefficient before calcium hydroxide should be 3 dollars $. And because there are 3 dollars $hydroxides in aluminum hydroxide, and 2 dollars $aluminum hydroxide contains 6 dollars $hydroxides, which is exactly the same as the number of hydroxides in 3 dollars $calcium hydroxide.
In summary, the chemical equation for the reaction of aluminum sulfate and calcium hydroxide is: $Al_ {2} (SO_ {4}) _ {3} + 3Ca (OH) _ {2} = 2Al (OH) _ {3}\ downarrow + 3CaSO_ {4} $. This formula is equal to the type and number of atoms, which is chemically reasonable.
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