Langyou Chemical
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Aluminum Sulfate Sodium Hydroxide Balanced Equation
The reaction between aluminum sulfuric acid and sodium hydroxide is a wonderful chemical reaction in the world. The reaction between aluminum sulfuric acid ($Al_ {2} (SO_ {4}) _ {3} $) and sodium hydroxide ($NaOH $) is very important. To understand the details, it is necessary to study the essence of the reaction and the method of balancing.
At the beginning, the two meet. The aluminum ion ($Al ^ {3 +} $) in aluminum sulfuric acid interacts with the hydroxide ion ($OH ^ {-} $) in sodium hydroxide. Aluminum ions are $+ 3 $valence and hydroxide ions are $- 1 $valence. According to the conservation of charge, it takes 3 dollars $hydroxide ions to combine with 1 dollar $aluminum ions to obtain electrically neutral aluminum hydroxide ($Al (OH) _ {3} $) precipitation.
However, sulfate ions ($SO_ {4} ^ {2 -} $) and sodium ions ($Na ^{ + }$） also moved. Sodium ions combine with sulfate ions to form sodium sulfate ($Na_ {2} SO_ {4} $).
Looking at this reaction, you can write the preliminary reaction formula first: $Al_ {2} (SO_ {4}) _ {3} + NaOH\ longrightarrow Al (OH) _ {3}\ downarrow + Na_ {2} SO_ {4} $.
But this formula is not balanced. First view sulfate, there are 3 dollars $sulfate in aluminum sulfate, so sodium sulfate should be preceded by 3 dollars $, that is, $Al_ {2} (SO_ {4}) _ {3} + NaOH\ longrightarrow Al (OH) _ {3}\ downarrow + 3Na_ {2} SO_ {4} $.
At this time, there are 6 dollars $sodium ions in sodium sulfate, so sodium hydroxide should be matched with 6 dollars $to get $Al_ {2} (SO_ {4}) _ {3} + 6NaOH\ longrightarrow Al (OH) _ {3}\ downarrow + 3Na_ {2} SO_ {4} $.
Looking at aluminum, there are 2 dollars $aluminum atoms in aluminum sulfuric acid, so aluminum hydroxide should be matched with 2 dollars $, that is, $Al_ {2} (SO_ {4}) _ {3} + 6NaOH = 2Al (OH) _ {3}\ downarrow + 3Na_ {2} SO_ {4} $.
After this step, the number of atoms of each element on the left and right sides of the reaction formula is equal, and the balance is completed. The balance of this reaction is the weight of the chemical foundation, and it is reasonable to be able to progress step by step on the road of chemistry and gain insight into the mysteries of various reactions.
At the beginning, the two meet. The aluminum ion ($Al ^ {3 +} $) in aluminum sulfuric acid interacts with the hydroxide ion ($OH ^ {-} $) in sodium hydroxide. Aluminum ions are $+ 3 $valence and hydroxide ions are $- 1 $valence. According to the conservation of charge, it takes 3 dollars $hydroxide ions to combine with 1 dollar $aluminum ions to obtain electrically neutral aluminum hydroxide ($Al (OH) _ {3} $) precipitation.
However, sulfate ions ($SO_ {4} ^ {2 -} $) and sodium ions ($Na ^{ + }$） also moved. Sodium ions combine with sulfate ions to form sodium sulfate ($Na_ {2} SO_ {4} $).
Looking at this reaction, you can write the preliminary reaction formula first: $Al_ {2} (SO_ {4}) _ {3} + NaOH\ longrightarrow Al (OH) _ {3}\ downarrow + Na_ {2} SO_ {4} $.
But this formula is not balanced. First view sulfate, there are 3 dollars $sulfate in aluminum sulfate, so sodium sulfate should be preceded by 3 dollars $, that is, $Al_ {2} (SO_ {4}) _ {3} + NaOH\ longrightarrow Al (OH) _ {3}\ downarrow + 3Na_ {2} SO_ {4} $.
At this time, there are 6 dollars $sodium ions in sodium sulfate, so sodium hydroxide should be matched with 6 dollars $to get $Al_ {2} (SO_ {4}) _ {3} + 6NaOH\ longrightarrow Al (OH) _ {3}\ downarrow + 3Na_ {2} SO_ {4} $.
Looking at aluminum, there are 2 dollars $aluminum atoms in aluminum sulfuric acid, so aluminum hydroxide should be matched with 2 dollars $, that is, $Al_ {2} (SO_ {4}) _ {3} + 6NaOH = 2Al (OH) _ {3}\ downarrow + 3Na_ {2} SO_ {4} $.
After this step, the number of atoms of each element on the left and right sides of the reaction formula is equal, and the balance is completed. The balance of this reaction is the weight of the chemical foundation, and it is reasonable to be able to progress step by step on the road of chemistry and gain insight into the mysteries of various reactions.
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